Q.
Consider a body, shown in figure, consisting of two identical balls, each of mass $M$ connected by a light rigid rod. If an impulse$J = Mv$ is impared to the body at one of its ends, what would be its angular velocity?
A) $v/L$
B) $2v/L$
C) $v/3L$
D) $v/4L$
Explanation
(a) Let $\omega$ be the angular velocity of the rod. Applying ,
Angular impulse = change in angular momentum about centre of mass of the system
[image:7_image135.emf]
$J.\frac{L}{2} = I_{c}\omega$
$\therefore$ $(Mv)\left( \frac{L}{2} \right) = (2)\left( \frac{ML^{2}}{4} \right).\omega\ $
$\therefore$ $\omega = \frac{v}{L}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.