(b) [image:7_image138.emf]
For the motion of the block
$mg - T = ma$ …(i)
For the rotation of the pulley
$\tau = TR = I\alpha$
$\Longrightarrow$ $T = \frac{1}{2}mR\alpha$ …(ii)
As string does not slip on the pulley
$a = R\alpha$ …(iii)
On solving Eqs. (i), (ii) and (iii)
$a = \frac{2g}{3}$