Q. A body is rolling without slipping on a horizontal surface and its rotational kinetic energy is equal to the translational kinetic energy. The body is
A) Disc
B) Sphere
C) Cylinder
D) Ring
Explanation
(d) $K_{R} = K_{T} \Rightarrow \frac{1}{2}mv^{2}\left( \frac{K^{2}}{R^{2}} \right) = \frac{1}{2}mv^{2} \Rightarrow \ \therefore\frac{K^{2}}{R^{2}} = 1$
$i.e.$ the body is ring
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.