Q. A coin is of mass 4.8 kg and radius one metre rolling on a horizontal surface without sliding with angular velocity 600 rotation/min. What is total kinetic energy of the coin ?

A) 360 J
B) 1440$\pi^{2}\ J$
C) 4000 $\pi^{2}\ J$
D) 600 $\pi^{2}\ J$
Explanation

(b) Angular velocity is given by
$\omega =$600 rotation/min
$= \frac{600 \times 2\pi}{60}rads^{- 1} = 20\pi\ rads^{- 1}$
Kinetic energy of coin which is due to rotation and translation is
$K = \frac{1}{2}\ I\omega^{2} + \frac{1}{2}mv^{2}$
$= \frac{1}{2} \times \frac{1}{2}mr^{2}\omega^{2} + \frac{1}{2}m(\omega r)^{2}$
$= \frac{1}{4} \times 4.8 \times (1)^{2}(20\pi)^{2} + \frac{1}{2} \times 4.8 \times (20\pi \times 1)^{2}$
$= 480\pi^{2} + 960\pi^{2} = 1440\pi^{2}J$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.