Q. A cylinder of $500\ g$ and radius $10\ cm$ has moment of inertia (about its natural axis)
A) $2.5 \times 10^{- 3}\ kg$-$m^{2}$
B) $2 \times 10^{- 3}\ kg$-$m^{2}$
C) $5 \times 10^{- 3}\ kg$-$m^{2}$
D) $3.5 \times 10^{- 3}\ kg$-$m^{2}$
Explanation
(a) $I = \frac{1}{2}MR^{2} = \frac{1}{2} \times 0.5 \times (0.1)^{2} = 2.5 \times 10^{- 3}kg - m^{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.