(d) $m_{1} = 2kg,\ m_{2} = 4kg,\ {\overrightarrow{v}}_{1} = 20m/s,{\overrightarrow{v}}_{2} = - 10m/s$
${\overrightarrow{v}}_{cm} = \frac{m_{1}{\overrightarrow{v}}_{1} + m_{2}{\overrightarrow{v}}_{2}}{m_{1} + m_{2}} = \frac{2 \times 20 - 4 \times 10}{2 + 4} = 0\ m/s$