The curve between $\log_{e}L$ and $\log_{e}P$ is ($L$ is the angular momentum and $P$ is the linear momentum)

Question

Dr. Abubacker · Accepted Answer

(a) $L = r\ P \Rightarrow \log_{e}{L = \log_{e}{P + \log_{e}r}}$
If graph is drawn between $\log_{e}L$ and $\log_{e}P$ then it will be straight line which will not pass through the origin

Q. The curve between $\log_{e}L$ and $\log_{e}P$ is ($L$ is the angular momentum and $P$ is the linear momentum)

Explanation

Reviewed by Dr. Abubacker

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