(d) As shown in figure, centre of mass of respective rods are at their respective mid points. Hence centre of mass of the system has coordinates ($X_{CM}$,$\ Y_{CM}$). then
[image:7_image158.emf]
$X_{CM} = \frac{m \times \frac{a}{2} + m \times \frac{a}{2} + m \times 0}{3m} = \frac{a}{3}$
$Y_{CM} = \frac{m \times 0 + m \times \frac{a}{2} + m \times 0}{3m} = \frac{a}{3}$