Q. A solid cylinder has mass $M$, length $L$ and radius $R$. The moment of inertia of this cylinder about a generator is
A) $M\left( \frac{L^{2}}{12} + \frac{R^{2}}{4} \right)$
B) $\frac{ML^{2}}{4}$
C) $\frac{1}{2}MR^{2}$
D) $\frac{3}{2}MR^{2}$
Explanation
(d) Generator axis of a cylinder is a line lying on it’s surface and parallel to axis of cylinder
By parallel axis theorem
$I = \frac{MR^{2}}{2} + MR^{2} = \frac{3}{2}MR^{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.