Q. Consider a body, shown in figure, consisting of two identical balls, each of mass $M$ connected by a light rigid rod. If an impulse $J = MV$ is imparted to the body at one of its ends, what would be its angular velocity
A) $V/L$
B) $2V/L$
C) $V/3L$
D) $V/4L$
Explanation
(a) Given system of two particles will rotate about its centre of mass
Initial angular momentum $= MV\left( \frac{L}{2} \right)$
Final angular momentum $= 2I\omega = 2M\left( \frac{L}{2} \right)^{2}\omega$
By the law of conservation of angular momentum
$MV\left( \frac{L}{2} \right) = 2M\left( \frac{L}{2} \right)^{2}\omega \Rightarrow \omega = \frac{V}{L}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.