Q. A sphere rolls down on an inclined plane of inclination $\theta$. What is the acceleration as the sphere reaches bottom
A) $\frac{5}{7}g\sin\theta$
B) $\frac{3}{5}g\sin\theta$
C) $\frac{2}{7}g\sin\theta$
D) $\frac{2}{5}g\sin\theta$
Explanation
(a) $a = \frac{g\sin\theta}{1 + \frac{K^{2}}{R^{2}}} = \frac{g\sin\theta}{1 + \frac{2}{5}} = \frac{5}{7}g\sin\theta$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.