(c) $\omega_{\min} = \frac{2\pi}{60}\frac{rad}{\min}$
and $\omega_{hr} = \frac{2\pi}{12 \times 60}\frac{rad}{\min}$
$\therefore$ $\frac{\omega_{\min}}{\omega_{hr}} = \frac{\frac{2\pi}{60}}{\frac{2\pi}{12 \times 60}}$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = \frac{12}{1}$