Q. The moment of inertia of a thin rod of mass $M$ and length $L$, about an axis perpendicular to the rod at a distance $\frac{L}{4}$ from one end is
A) $\frac{{ML}^{2}}{6}$
B) $\frac{{ML}^{2}}{12}$
C) $\frac{{7ML}^{2}}{24}$
D) $\frac{{7ML}^{2}}{48}$
Explanation
(d) $I_{CD} = I_{CM} + M\left( \frac{L}{4} \right)^{2}$
[image:7_image172.emf]
$= \frac{ML^{2}}{12} + \frac{ML^{2}}{16} = \frac{7ML^{2}}{48}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.