Q. A sphere of mass $10kg$ and radius $0.5m$ rotates about a tangent. The moment of inertia of the solid sphere is
A) $5\ kg$-$m^{2}$
B) $2.7\ kg$-$m^{2}$
C) $3.5\ kg$-$m^{2}$
D) $4.5\ kg$-$m^{2}$
Explanation
(c) $I = \frac{7}{5}MR^{2} = \frac{7}{5} \times 10 \times (0.5)^{2} = 3.5kg - m^{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.