Q. The moment of inertia of a solid sphere of mass $M$ and radius $R$ about the tangent on its surface is
A) $\frac{7}{5}{MR}^{2}$
B) $\frac{4}{5}{MR}^{2}$
C) $\frac{2}{5}{MR}^{2}$
D) $\frac{1}{2}{MR}^{2}$
Explanation
(a) Moment of inertia of the solid sphere of mass $M$ and radius $R$ about is tangent
$I = I_{0} + MR^{2}$
(According to theorem of parallel axis)
$= \frac{2}{5}MR^{2} + MR^{2}\ \ \left( {\because I}_{0} = \frac{2}{5}MR^{2} \right)$
$I = \frac{7}{5}MR^{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.