(b) According to theorem of parallel axes, moment of inertia of a rod about one if its ends
$= \frac{Ml^{2}}{12} + \frac{Ml^{2}}{4} = \frac{Ml^{2}}{3}$
$\therefore$ Moment of inertia of two rods about $Z$-axis=Moment of inertia of 2 rods placed along $X$ and $Y$-axis $= \frac{2Ml^{2}}{3}$