(a) M.I. of rod (1) about $Z -$ axis, $I_{1} = \frac{Ml^{2}}{3}$
M.I. of rod (2) about $Z -$ axis, $I_{2} = \frac{Ml^{2}}{3}$
M.I. of rod (3) about $Z -$ axis, $I_{3} = 0$
Because this rod lies on $Z$-axis
$\therefore I_{system} = I_{1} + I_{2} + I_{3} = \frac{2Ml^{2}}{3}$