(c) Applying the principle of conservation of angular momentum,
$\left( I_{1} + I_{2} \right)\omega = I_{1}\omega_{1} + I_{2}\omega_{2}$
$\left( 6 + I_{2} \right)\frac{400}{60} \times 2\pi = 6 \times \frac{600}{60} \times 2\pi + I_{2} \times 0$
Which gives, $I_{2} = 3\ kg\ m^{2}$