Q. The wheel of a car is rotating at the rate of 1200 revolutions per $minute$. On pressing the accelerator for $10\ seconds$. It starts rotating at 4500 revolutions per $minute$. The angular acceleration of the wheel is
A) $30\ radians/second^{2}$
B) $1880\ degrees/second^{2}$
C) $40\ radians/second^{2}$
D) $1980\ degrees/second^{2}$
Explanation
(d) $\alpha = \frac{2\pi(n_{2} - n_{1})}{t} = \frac{2\pi\left( \frac{4500 - 1200}{60}\ \right)}{10}rad/s^{2}$
$= \frac{2\pi\frac{3300}{60}}{10} \times \frac{360}{2\pi}\frac{degree}{s^{2}}\alpha = 1980\ degree/s^{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.