Q. A point $P$ on the rim of wheel is initially at rest and in contact with the ground. Find the displacement of the point $P$ if the radius of the wheel is $5\ m$ and the wheel rolls forward through half a revolution
A) $5\ m$
B) $10\ m$
C) $2.5\ m$
D) $5(\sqrt{\left( \pi^{2} + 4 \right)}\ )m$
Explanation
(d) Displacement of point $P$ after half revolution
$PP^{'} = \sqrt{(\pi R)^{2} + (2R)^{2}} = R\sqrt{\pi^{2} + 4} = 5\sqrt{\pi^{2} + 4}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.