Q. An athlete throws a discus from rest to a final angular velocity of 15 ${rads}^{- 1}$ in 0.270 s before releasing it. During acceleration, discus moves a circular arc of radius 0.810 m Acceleration of discus before it is released is …. ${ms}^{- 2}$

A) 45
B) 182
C) 187
D) 192
Explanation

(a) $\omega = \omega_{0} + \alpha t$
$\Rightarrow$ $\omega = 0 + \alpha t$
$\Rightarrow$ $\alpha = \frac{15}{0.270}\ rads^{- 2}$
Now, $a = r,\ \alpha = 0.81 \times \frac{15}{0.270} = 45\ ms^{- 2}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.