Q. Moment of inertia of a thin circular disc of mass $M$ and radius $R$ about any diameter is
A) $\frac{MR^{2}}{4}$
B) $\frac{MR^{2}}{2}$
C) $MR^{2}$
D) $2MR^{2}$
Explanation
The correct answer is Option A: $\frac{MR^{2}}{4}$.
A detailed explanation for this question is being prepared.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.