Q. A spherical planet for out in space has a mass $M_{0}$ and diameter $D_{0}$. A particle of mass $m$ falling freely new the surface of this planet will experience an acceleration due to gravity which is equal to
A) $GM_{0}/D_{0}^{2}$
B) $4mGM_{0}/D_{0}^{2}$
C) $4GM_{0}/D_{0}^{2}$
D) $G{mM}_{0}/D_{0}^{2}$
Explanation
(c) $g = \frac{GM}{R^{2}} = \frac{GM_{0}}{\left( D_{0}/2 \right)^{2}} = \frac{4GM_{0}}{D_{0}^{2}}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.