Q. Assuming that the earth is a sphere of radius $R_{E}$ with uniform density, the distance from its centre at which the acceleration due to gravity is equal to $\frac{g}{3}$ ($g$ is the acceleration due to gravity on the surface of earth) is

A) $\frac{R_{E}}{3}$
B) $\frac{2R_{E}}{3}$
C) $\frac{R_{E}}{2}$
D) $\frac{R_{E}}{4}$
Explanation

The correct answer is Option A: $\frac{R_{E}}{3}$.

A detailed explanation for this question is being prepared.

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

Want more practice?
Practice Gravitation MCQs