Q. Gravitational potential on the surface of earth is ($M =$mass of the earth, $R =$ radius of earth)
A) $- GM/2R$
B) $- gR$
C) $gR$
D) $GM/R$
Explanation
(b) Gravitational potential at a point on the surface of earth
$V = \frac{- GM}{R} = \frac{- gR^{2}}{R} = - gR$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.