A clock S is based on oscillation of a spring and a clock P is based on pendulum motion. Both clocks run at the same rate on earth. On a planet having the same density as earth but twice the radius

Question

Dr. Abubacker · Accepted Answer

(b) $g = \frac{4}{3}\piho GR$. If density is same then $g \propto R$
According to problem $R_{p} = 2R_{e}	herefore g_{p} = 2g_{e}$
For clock $P$ (based on pendulum motion) $T = 2\pi\sqrt{\frac{l}{g}}$
Time period decreases on planet so it will run faster because $g_{p} > g_{e}$
For clock $S$ (based on oscillation of spring) $T = 2\pi\sqrt{\frac{m}{k}}$
So it does not change

Q. A clock S is based on oscillation of a spring and a clock P is based on pendulum motion. Both clocks run at the same rate on earth. On a planet having the same density as earth but twice the radius

Explanation

Reviewed by Dr. Abubacker

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