Q. The rotation period of an earth satellite close to the surface of the earth is 83 min. the satellite in a orbit at a distance of three times earth radii from its surface will be
A) 83 min
B) $83 \times \sqrt{8}$ min
C) 664 min
D) 249 min
Explanation
(c) $T_{2} = T_{1}\left( \frac{r_{2}}{r_{1}} \right)^{2/3} = 83\left( \frac{R + 3R}{R} \right)^{3/2}$
$= 83 \times 8 = 664\ min$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.