Q. The mass of the moon is $7.34 \times 10^{22}$ kg and the radius is $1.74 \times 10^{6}$m. the value of gravitational field intensity will be
A) $1.45\ Nkg^{- 1}$
B) $1.55\ Nkg^{- 1}$
C) $1.7\ Nkg^{- 1}$
D) $1.62\ Nkg^{- 1}$
Explanation
(d) Gravitational field intensity
$I = \frac{GM}{R^{2}} = \frac{6.6 \times 10^{- 11} \times 7.34 \times 10^{22}}{\left( 1.74 \times 10^{6} \right)^{2}}$
$= 1.62\ Nkg^{- 1}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.