Satellite $A$ and $B$ are revolving around the orbit of earth. The mass of $A$ is 10 times of $mass\ of\ B.The\ ratio\ of\ time\ period\ \left( \frac{T_{A}}{T_{B}} \right)is\ $

Question

Dr. Abubacker · Accepted Answer

(b) Time period of satellite
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ T = 2\pi\sqrt{\frac{(R_{e} + h)^{2}}{gR_{e}^{2}}}$
$Where,\ \ R_{e} = Radius\ of\ earth,$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ h = Height\ from\ earth\ surface\ .$
Time period not depend on mass. So, time period of both satellite will be equal.

Q. Satellite $A$ and $B$ are revolving around the orbit of earth. The mass of $A$ is 10 times of $mass\ of\ B.The\ ratio\ of\ time\ period\ \left( \frac{T_{A}}{T_{B}} \right)is\ $

Explanation

Reviewed by Dr. Abubacker

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