Q. A satellite of mass $m$ is circulation around the earth with constant angular velocity. If radius of the orbit is $R_{0}$ and mass of the earth $M$, the angular momentum about the centre of the earth is
A) $m\sqrt{GMR_{0}}$
B) $M\sqrt{GMR_{0}}$
C) $m\sqrt{\frac{GM}{R_{0}}}$
D) $M\sqrt{\frac{GM}{R_{0}}}$
Explanation
(a) Angular momentum $=$ Mass $\times$ Orbital velocity $\times$ Radius
$= m \times \left( \sqrt{\frac{GM}{R_{0}}} \right) \times R_{0} = m\sqrt{GMR_{0}}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.