Q. The escape velocity for a body projected vertically upwards from the surface of earth is ${11\ kms}^{- 1}$. If the body is projected at an angle of $45{^\circ}$ with the vertical, the escape velocity will be
A) ${11\ \sqrt{2}kms}^{- 1}$
B) ${22\ kms}^{- 1}$
C) ${11\ kms}^{- 1}$
D) $11/\sqrt{2}\ {ms}^{- 1}$
Explanation
(c) The escape velocity is independent of angle of projection, hence, it will remain same $ie.\ {11\ kms}^{- 1}.$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.