Q. The orbital angular momentum of a satellite revolving at a distance $r$ from the centre is $L$. If the distance is increased to $16r$, then the new angular momentum will be
A) $16\ L$
B) $64\ L$
C) $\frac{L}{4}$
D) $4\ L$
Explanation
(d) $L = mvr = m\left( \sqrt{\frac{GM}{r}} \right)r = m\sqrt{GMr}\ \therefore L \propto \sqrt{r}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.