Q. Radius of orbit of satellite of earth is $R$. Its kinetic energy is proportional to
A) $\frac{1}{R}$
B) $\frac{1}{\sqrt{R}}$
C) $R$
D) $\frac{1}{R^{3/2}}$
Explanation
(a) $K.E. = \frac{GMm}{2R}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.