If the value of g acceleration due to gravity at earth surface is $10\ ms^{- 2}$. Its value in $ms^{- 2}$ at the centre of the earth, which is assumed to be a sphere of radius $R$ metre and uniform mass density is

Question

Dr. Abubacker · Accepted Answer

(d) Let the gravitational force on a body mass $m$ at $O$ due to moon of mass $M$ and earth of mass $8/M$ be zero, where $EO = x$ and $MO = (r - x)$. Then,
$\frac{G81M 	imes m}{x^{2}} = \frac{GM\ m}{(r - x)^{2}}$
or $\frac{81}{x^{2}} = \frac{1}{(r - x)^{2}}$
or $\frac{9}{x} = \frac{1}{(r - x)^{\ }}$
On solving; $x = 9r/10$

Q. If the value of g acceleration due to gravity at earth surface is $10\ ms^{- 2}$. Its value in $ms^{- 2}$ at the centre of the earth, which is assumed to be a sphere of radius $R$ metre and uniform mass density is

Explanation

Reviewed by Dr. Abubacker

Want more practice?