(c) $g_{p} = g_{e}\left( \frac{M_{p}}{M_{e}} \right)\left( \frac{R_{e}}{R_{p}} \right)^{2} = 9.8\left( \frac{1}{80} \right)(2)^{2}$ $= 9.8/20 = 0.49m/s^{2}$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.