Q. The escape velocity of a planet having mass 6 times and radius 2 times as that of earth is
A) $\sqrt{3}\ V_{e}$
B) $3\ V_{e}$
C) $\sqrt{2}\ V_{e}$
D) $2\ V_{e}$
Explanation
(a) $\frac{v_{p}}{v_{e}} = \sqrt{\frac{M_{p}}{M_{e}} \times \frac{R_{e}}{R_{p}}} = \sqrt{6 \times \frac{1}{2}} = \sqrt{3}\ \therefore v_{p} = \sqrt{3}v_{e}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.