The maximum and minimum distances of a comet from the sun are $8 imes 10^{12}m$ and $1.6 imes 10^{12}m$. If its velocity when nearest to the sun is $60\ m/s$, what will be its velocity in $m/s$ when it is farthest

Question

The maximum and minimum distances of a comet from the sun are $8 	imes 10^{12}m$ and $1.6 	imes 10^{12}m$. If its velocity when nearest to the sun is $60\ m/s$, what will be its velocity in $m/s$ when it is farthest

Dr. Abubacker · Accepted Answer

(a) By conservation of angular momentum $mvr =$ constant
$v_{\min} 	imes r_{\max} = v_{\max} 	imes r_{\min}$
$	herefore\ v_{\min} = \frac{60 	imes 1.6 	imes 10^{12}}{8 	imes 10^{12}} = \frac{60}{5} = 12\ m/s$

Q. The maximum and minimum distances of a comet from the sun are $8 \times 10^{12}m$ and $1.6 \times 10^{12}m$. If its velocity when nearest to the sun is $60\ m/s$, what will be its velocity in $m/s$ when it is farthest

Explanation

Reviewed by Dr. Abubacker

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