(a) Escape velocity $v = \sqrt{2gR}$
$\therefore\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \frac{v_{1}}{v_{2}} = \sqrt{\frac{g_{1}}{g_{2}} \times \frac{R_{1}}{R_{2}}}$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = \sqrt{g \times K} = {(Kg)}^{1/2}$