Q. The escape velocity for a body of mass 1 kg from the earth’s surface is ${11.2\ kms}^{- 1}$. The escape velocity for a body of mass 100 kg would be
A) ${11.2 \times 10}^{2}{kms}^{- 1}$
B) ${112\ kms}^{- 1}$
C) ${11.2\ kms}^{- 1}$
D) $11.2 \times 10^{- 2}{kms}^{- 1}$
Explanation
(c) At a certain velocity of projection of the body will go out of the gravitational field of earth and never to return to earth. The initial velocity is called escape velocity
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ v_{e} = \sqrt{2gR}$
Where $g$ is acceleration due to gravity and $R$ the radius. As is clear from above formula, that escape velocity dose not depends upon mass of body hence, it will be same for a body of 100kg as for 1kg body.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.