Q. The escape velocity from earth is $v_{es}$. A body is projected with velocity $2v_{es}$ with what constant velocity will it move in the inter planetary space
A) $v_{es}$
B) $3v_{es}$
C) ${\sqrt{3}v}_{es}$
D) ${\sqrt{5}v}_{es}$
Explanation
(c) Velocity of body in inter planetary space $v' = \sqrt{v^{2} - v_{es}^{2}}$
Where $v_{es}$= escape velocity and
$v =$ velocity of projection
$\therefore v^{'} = \sqrt{\left( 2v_{es} \right)^{2} - v_{es}^{2}} = \sqrt{3v_{es}^{2}} \Rightarrow v^{'} = \sqrt{3}v_{es}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.