Q. The orbit of geostationary satellite is circular, the time period of satellite depends on (i) mass of the satellite (ii) mass of the earth (iii) radius of the orbit (iv) height of the satellite from the surface of earth Which of the following correct?
A) (i) only
B) (i) and (ii)
C) (i), (ii) and (iii)
D) (ii), (iii) and (iv)
Explanation
(d) Time period of satellite
$T \propto \frac{1}{M^{1/2}},\ where\ M\ is\ mass\ of\ earth.$
$\propto (R + h)^{3/2}$ where R is radius of the orbit, $h$ is the height of satellite from the earth’s surface.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.