Q. The escape velocity of an object from the earth depends upon the mass of the earth $(M)$, its mean density, $(\rho)$, its radius $(R)$ and the gravitational constant $(G)$. Thus the formula for escape velocity is
A) $v = R\sqrt{\frac{8\pi}{3}G\rho}$
B) $v = M\sqrt{\frac{8\pi}{3}GR}$
C) $v = \sqrt{2GMR}$
D) $v = \sqrt{\frac{2GM}{R^{2}}}$
Explanation
The correct answer is Option A: $v = R\sqrt{\frac{8\pi}{3}G\rho}$.
A detailed explanation for this question is being prepared.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.