Q. Three particles each of mass $m$ are kept at verities of an equilateral triangle of side $\ L.$ The gravitational field at centre due to these particle is
A) Zero
B) $\frac{3GM}{L^{2}}$
C) $\frac{9GM}{L^{2}}$
D) $\frac{12}{\sqrt{3}}\frac{GM}{L^{2}}\ $
Explanation
(a) The net force acting on a unit mass placed at $O\ $due to three equal masses $M$ at verities $A,B\ and\ C$ is the gravitational field intensity at point $O$. The gravitational force on the particle placed at the point of intersection of three medians.
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Since, the resultant of $\mathbf{F}_{1}\ and\ \mathbf{F}_{2}$ is equal and opposite to $\mathbf{\ F}_{3}$.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.