Q. The height at which the weight of a body becomes $1/16^{th}$, its weight on the surface of earth (radius $R$), is
A) $5R$
B) $15R$
C) $3R$
D) $4R$
Explanation
(c) $g^{'} = \frac{g}{\left( 1 + \frac{h}{R} \right)^{2}}$
$\frac{g}{16} = \frac{g}{\left( 1 + \frac{h}{R} \right)^{2}}$
$\left( 1 + \frac{h}{R} \right)^{2} = 16$
$1 + \frac{h}{R} = 4$
$\frac{h}{R} = 3$
$h = 3R$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.