(c) $H = \frac{u^{2}}{2g} \Rightarrow H \propto \frac{1}{g} \Rightarrow \frac{H_{B}}{H_{A}} = \frac{g_{A}}{g_{B}}$
Now $g_{B} = \frac{g_{A}}{12}$ as $g \propto \rho R$
$\therefore\frac{H_{B}}{H_{A}} = \frac{g_{A}}{g_{B}} = 12$
$\Rightarrow H_{B} = 12 \times H_{A} = 12 \times 1.5 = 18m$