Q. Two planets of mean distance $d_{1}$ and $d_{2}$ from the sun and their frequencies are $n_{1}$ and $n_{2}$ respectively then
A) $n_{1}^{2}d_{1}^{2} = n_{2}d_{2}^{2}$
B) $n_{2}^{2}d_{2}^{3} = n_{1}^{2}d_{1}^{3}$
C) $n_{1}d_{1}^{2} = n_{2}d_{2}^{2}$
D) $n_{1}^{2}d_{1} = n_{2}^{2}d_{2}$
Explanation
(b) $\frac{T^{2}}{R^{3}} = \frac{T^{2}}{d^{3}} = \frac{1}{n^{2}d^{3}} =$ constant
$\therefore n_{1}^{2}d_{1}^{3} = n_{2}^{2}d_{2}^{3}$ [where $n =$ frequency]
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.