Q. For a satellite moving in an orbit around the earth, the ratio of kinetic energy to potential energy is
A) 2
B) $\frac{1}{2}$
C) $\frac{1}{\sqrt{2}}$
D) $\sqrt{2}$
Explanation
(b) For a moving satellite kinetic energy $= \frac{GMm}{2r}$
Potential energy $= \frac{- GMm}{r} \Rightarrow \ \therefore\ \frac{Kinetic\ energy}{Potential\ energy} = \frac{1}{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.