Q. The period of a satellite in a circular orbit of radius $R$ is $T$, the period of another satellite in a circular orbit of radius $4R$ is
A) $4T$
B) $T/4$
C) $8T$
D) $T/8$
Explanation
(c) $\frac{T_{1}}{T_{2}} = \left( \frac{R_{1}}{R_{2}} \right)^{3/2} = \left( \frac{R}{4R} \right)^{3/2} \Rightarrow T_{2} = 8T_{1}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.