Q. Radius of earth is around $6000\ km$. The weight of body of height of $6000\ km$ from earth surface becomes
A) Half
B) One-fourth
C) One third
D) No change
Explanation
(b) $g^{'} = g\left( \frac{R}{R + h} \right)^{2} \Rightarrow$ when$\ h = R$ then $g^{'} = \frac{g}{4}$
So the weight of the body at this height will become one-fourth
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.