Q. In the previous question, the angular speed of $S_{2}$ as actually observed by an astronaut is $S_{1}\ $
A) $\frac{\pi}{2}radh^{- 1}$
B) $\pi\ radh^{- 1}$
C) $\frac{2\pi}{3}\ radh^{- 1}$
D) $\frac{\pi}{3}\ radh^{- 1}$
Explanation
(d) $\omega = \frac{|v|}{R_{2} - R_{1}} = \frac{\pi \times 10^{4}}{4 \times 10^{4} - 1 \times 10^{4}} = \frac{\pi}{3}\ radh^{- 1}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.